Computer Science Canada

Exiting Loop After a Delay Help!
Author:  heroes100 [ Thu Nov 05, 2009 6:54 pm ]
Post subject:  Exiting Loop After a Delay Help!
What is it you are trying to achieve?
I am trying to get a loop to stop after a delay of w.e time.

What is the problem you are having?
I have a loop which generates random symbols and i would like it to stop generating these symbols after a designated time limit.

Describe what you have tried to solve this problem
I have tried to create a variable and make it add to the variable every loop and once it ='s a number it stopes but this will not work for i get a syntax error. :/

Post any relevant code (You may choose to attach the file instead of posting the code if it is too long)
Turing:


loop
let := Rand.Int (1,122)
put chr (let), ""..
end loop
end loading



Please specify what version of Turing you are using
4.11 (or i can also load it with 4.0.5)
Author:  BigBear [ Thu Nov 05, 2009 6:58 pm ]
Post subject:  RE:Exiting Loop After a Delay Help!
You have no exit condition

I think you might want to use a for loop
Author:  heroes100 [ Thu Nov 05, 2009 7:34 pm ]
Post subject:  RE:Exiting Loop After a Delay Help!
How can i make "let" a random int between 1-122 in a for loop?
Also when it is a for loop how can i exit it with a delay?? :/
Author:  Kharybdis [ Thu Nov 05, 2009 8:01 pm ]
Post subject:  Re: Exiting Loop After a Delay Help!
Turing:
var let : int
var count := 1
loop
    randint (let, 1, 5) % (integer value, lowest, highest)
    count += 1
    put let
    exit when let = 2 % exit condition if let = 2
end loop

put "let appeared, ", count, " times."
Author:  heroes100 [ Thu Nov 05, 2009 8:25 pm ]
Post subject:  RE:Exiting Loop After a Delay Help!
Thanks for the responses. I have found a way around this. Even though the main question of how you can make a loop stop after a delay hasn't been answered but i have solved the problem. So all is well thx. Very Happy
Author:  Superskull85 [ Thu Nov 05, 2009 10:52 pm ]
Post subject:  Re: Exiting Loop After a Delay Help!
What do you mean by "stop after a delay?" Do you mean something like this:

Turing:
loop
   let := Rand.Int (1,122)
   put chr (let), ""..
   delay (100)
   exit
end loop

Or do you mean like what Kharybdis posted:

Turing:
var let : int
var count := 1
loop
    randint (let, 1, 5) % (integer value, lowest, highest)
    count += 1
    put let
    exit when let = 2 % exit condition if let = 2
end loop

put "let appeared, ", count, " times."

Or do you means something like this:

Turing:
var let : int
var count : int := 0
loop
    let := Rand.Int (1, 122)
    count += 1
    put chr (let), "" ..
    exit when count = 10
end loop

I am a little confused about what you mean.

Anyways, if you wanted to use a for loop with a random upper bound than you could do something like:

Turing:
for i : 1 .. Rand.Int (1, 222)
    put chr (i) ..
end for

What did you do to solve the problem?
Author:  heroes100 [ Fri Nov 06, 2009 8:22 am ]
Post subject:  RE:Exiting Loop After a Delay Help!
I meant more of the first but i do not know if that will still generate enough chars. as i need. I have ended up doing the 3rd thing you posted though but i was wanting it to generate random chars. and then stop after a set delay. But there is no need atm because i fixed it.
Author:  B-Man 31 [ Fri Nov 06, 2009 11:33 am ]
Post subject:  Re: Exiting Loop After a Delay Help!
if your trying to do it after a set amount of time, you could do something like this, more or less:

Turing:


var timepassed : int

loop
    timepassed := Time.Elapsed % starts a timer function
    let := Rand.Int (1, 122)
    put chr (let), "" ..
    if Time.Elapsed - timepassed >= 3000 then % the 3000 represents 3 seconds, change it to whatever you want
        exit %so basicly, if more than 3 seconds passed, then exit the loop
    end if
end loop

:


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