Computer Science Canada

ball bounce off the brick
Author:  uknowhoiam [ Tue Apr 14, 2009 9:12 pm ]
Post subject:  ball bounce off the brick
What is it you are trying to achieve?
I want the ball to bounce off the brick


What is the problem you are having?
the ball will not bounce off the bricks

Describe what you have tried to solve this problem
Turing:
if ballx >= brickx and ballx <= brickx2 and bally = bricky2  then
        ypos := 10 - gravity
    end if


That is what i have done

Post any relevant code (You may choose to attach the file instead of posting the code if it is too long)



Turing:

View.Set ("graphics:650;400,offscreenonly")
var ballx, bally, xpos, xpos2, ypos, gravity : real
var line, Colour, face, brick_colour, brickx, bricky, brickx2, bricky2 : int
var keys : array char of boolean

Colour := 119
face := 255
line := 50
ballx := line + maxx - 100
bally := line
xpos := 1
xpos2 := -1
ypos := 8
gravity := .25
brickx := Rand.Int (0, maxx - 10)
brickx2 := brickx + 40
bricky := Rand.Int (10, 170)
bricky2 := bricky + 15
brick_colour := brown

procedure Player
    drawfilloval (round (ballx), round (bally), 10, 10, Colour)     %body
    drawoval (round (ballx), round (bally), 10, 10, face)     %body outline
    drawfilloval (round (ballx) - 3, round (bally) + 2, 1, 1, face)     %left eye
    drawfilloval (round (ballx) + 3, round (bally) + 2, 1, 1, face)     %right eye
    drawfillarc (round (ballx), round (bally) - 2, 2, 4, 180, 360, face)     %smile
end Player

procedure Brick
    drawfillbox (brickx, bricky, brickx2, bricky2, brick_colour)
end Brick
loop
    Brick
    Player
    View.Update
    delay (10)
    cls

    ballx -= xpos
    bally += ypos
    ypos -= gravity

    if ballx >= brickx and ballx <= brickx2 and bally = bricky2 + 25 then
        ypos := 10 - gravity
    end if

    if bally <= 15 then
        ypos := 10 - gravity
    end if

    if ballx > maxx + 10 then
        ballx := -10
    end if

    if ballx < -10 then
        ballx := maxx + 10
    end if

    if xpos >= 3 then
        xpos := 2
    end if
    if xpos <= -3 then
        xpos := -2
    end if

    Input.KeyDown (keys)
    if keys (KEY_RIGHT_ARROW) then
        xpos -= 1
    end if
    if keys (KEY_LEFT_ARROW) then
        xpos += 1
    end if
end loop
%Just test it your self



Please specify what version of Turing you are using
<Answer Here>
[syntax=""][/syntax][syntax=""][/syntax]
Author:  Tony [ Tue Apr 14, 2009 9:26 pm ]
Post subject:  RE:ball bounce off the brick
I'm not exactly sure what those variables are, but
code:

and bally = bricky2

sounds awfully specific.
Author:  TokenHerbz [ Wed Apr 15, 2009 3:15 am ]
Post subject:  Re: ball bounce off the brick
hey bud, yea you gotta make your var's names better Razz anyways check out the part i changed in your code,

code:

%if ballx >= brickx and ballx <= brickx2 and bally = bricky2 + 25 then
     %   ypos := 10 - gravity
  %  end if
 
  %%may i recomend you use a ball size variable, if you dicide to change the size later it would suck to change all the numbers in your code.
 
  %%Need to find point of contact with the brick...
    if bally <= bricky2 and bally +10 >= bricky and ballx <= brickx2 and ballx+10 >= brickx then  %%i assume 10 is the size of the ball?
        put "POINT OF CONTACT"
        Input.Pause
    end if


try to understand why that works, its rough lol but better then nothing, it IS 4:15 am lol im off to bed..
Author:  uknowhoiam [ Wed Apr 15, 2009 6:54 pm ]
Post subject:  RE:ball bounce off the brick
Turing:
if bally <= bricky2


The problem with the above code is that, if the ball if below the brick (like not even touching it)
the ball will boucne off

But Hey you got it to bounce Smile
Author:  Dusk Eagle [ Wed Apr 15, 2009 10:03 pm ]
Post subject:  Re: RE:ball bounce off the brick
uknowhoiam @ Wed Apr 15, 2009 7:54 pm wrote:
Turing:
if bally <= bricky2


The problem with the above code is that, if the ball if below the brick (like not even touching it)
the ball will boucne off



That's true, but you've seen the basic idea so now you know how it's done. Now you just have to apply your knowledge to all four sides of the ball and brick to make collision detection complete.

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