Computer Science Canada And, or, xor, etc. on integers? |
| Author: | Briggs [ Wed Feb 25, 2009 5:58 pm ] |
| Post subject: | And, or, xor, etc. on integers? |
(I'm using Dev-C++ 4.9.9.2 with g++, before anybody asks.) For some reason, (int xor int) will xor the binary values and return one result, but if I try doing (int and int) or (int or int) it gives me 0 and 1 instead. For example: 9 xor 5 gives me 12, which is correct. 9 or 5 gives me 1, when it should give me 13. 9 and 5 gives me 1, which is correct, but 9 and 6 also gives me 1 when it should give me 0. I know this has to do with the fact that in boolean algebra, any nonzero values are treated as 1, but I have no idea how to make it so that "and" and "or" also compare the binary values of integers. Please help? |
|
| Author: | DanielG [ Wed Feb 25, 2009 6:21 pm ] |
| Post subject: | RE:And, or, xor, etc. on integers? |
you have to use the binary operators (& for and instead of the regular && and | for or instead of the regular ||) |
|
| Author: | Tony [ Wed Feb 25, 2009 11:20 pm ] |
| Post subject: | RE:And, or, xor, etc. on integers? |
as Daniel pointed out. && is a boolean and, returning true/false (1/0) while & is a binary and, which is what you are looking for. |
|