Computer Science Canada [help] can anyone help me??? |
Author: | chelseafc [ Mon Dec 22, 2008 7:03 pm ] | ||||
Post subject: | [help] can anyone help me??? | ||||
Can anyone explain to me how this recursive method returns the number of ways n can be written as a sum of k positive integers??? I don't understand why the sum of the ways n-1 can be written as k-1 integers and n-k can be written as k integers are equal to the ways that n can be written as k integers. Thanks!!! Mod Edit: Remember to use syntax tags! Thanks
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Author: | jbking [ Mon Dec 22, 2008 10:10 pm ] |
Post subject: | RE:[help] can anyone help me??? |
The partition(n-1,k-1) is a list that you could simply add a + 1 to to get some of the partition solutions for (n,k) where 1 is part of the solution. Now, as for the other value, think about what the other combinations would be where there isn't a 1 in the list as those were counted above. Now, what do all these look like? Well, if you subtract 1 from each integer the total will now be (n-k) as there were k values and you still want to use k integers to produce that sum. |
Author: | chelseafc [ Mon Dec 22, 2008 10:30 pm ] |
Post subject: | RE:[help] can anyone help me??? |
OH! I finally understand now thanks to your explanation!! Actually this is a dwite question on 2007 January. I now completely understand it!! Thank you very much,jbking!! |
Author: | jbking [ Mon Dec 22, 2008 10:57 pm ] |
Post subject: | Re: [help] can anyone help me??? |
Just as a side note, this type of problem is commonly found in a branch of Mathematics called "Combinatorics" where generating functions tend to be used to find various solutions. Combinatorics, to me at least, is generally a fancy way of counting things usually called "Enumeration." It does have its interesting elements, like how many different Lotto 6/49 combinations are there or how many ways can one schedule a tournament using what are called "Combinatorial Designs." Waterloo has a "Combinatorics and Optimization" department within the Math faculty that may be of interest if you like this type of problem. |