Computer Science Canada 32bit floating point representation |
| Author: | stupidchief [ Sat Sep 20, 2008 8:38 am ] |
| Post subject: | 32bit floating point representation |
Hi, How would you represent the following number in 32bit binary? -7 x 2^-87 A brief explanation would be helpful. I understand the basics i.e. first bit is sign bit - next 8 are biased exponent etc.. |
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| Author: | OneOffDriveByPoster [ Sat Sep 20, 2008 9:07 am ] |
| Post subject: | Re: 32bit floating point representation |
stupidchief @ Sat Sep 20, 2008 8:38 am wrote: Hi,
How would you represent the following number in 32bit binary? -7 x 2^-87 A brief explanation would be helpful. I understand the basics i.e. first bit is sign bit - next 8 are biased exponent etc.. Just one example... then 7 in binary: 111 Normalize: 7 = 1.11b * 2^+2 So, exponent field is: -87 + 2 + 127 = 42 = 00101010b Your float: 1 001 0101 0 110... or hex 95 60 00 00 |
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| Author: | stupidchief [ Sat Sep 20, 2008 9:15 am ] |
| Post subject: | Re: 32bit floating point representation |
Thanks a lot. The -7 was confusing me. wasn't sure if you were supposed to use a 2's complement binary version of -7 |
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