1. completely wrong. Wrong answer, and the reasoning isn't even relevant to the question asked (also faulty on its own).

2,3 seem alright.

where are you getting 40 Mbps from? That's 10 times as fast as Sympatico's high-speed broadband.

Using MPEG techniques, video presentations can be successfully relayed over communication paths that provide transfer rates of 40 Mbps.

You are storing data (space), not memory (memory is in RAM). You are also backing up more than 50 GB of data (it's a somewhat of a trick question).

CDs are obviously not reasonable, but how many DVDs will it take?

Any suggestions would be appreciated.

5. The following message was originally transmitted with odd parity in each short bit string. In which strings have errors definitely occurred?
I answered:
11001, 10011, 10110, 11111, 10001, and 10101.

6. Suppose a 24-bit code is generated by representing each symbol by three consecutive copies of its ASCII representation (for example, the symbol A is represented by the bit string 010000010100000101000001). What error-correcting properties does this new code have?
I answered:
Have three odd parity every third interval of string, if required.

7. In the following case, the different bit strings represent the same value but in different numeric encoding systems. Identify each value and the encoding systems used to represent it.
11111010 0011 1011
I answered:
(didn't answer, because I don't know the answer to it)

Why did you make so many threads, and why are you asking us this?

Also i am starting to get a bit consered that you are almost asking us to do your home work for you by posting all thess questions (even tho some have soultions). Your realy should be trying a bit harder to find the soultion on your own first (by looking in your text book or using google) befor posting. I personaly am trying to give you more tips and set you in the right direction rather then just given out anwsers, however if other users do then you will not learn much.

oper @ 2008-03-20, 5:40 pm"]2. How many bytes of storage space would be required to store a 400-page novel in which each page contains 3500 characters if ASCII were used? How many bytes would be required if Unicode were used?
I answered:
1 character in ASCII = 8 bits = 1 byte, 1 character in Unicode = 16 bits = 2 bytes
(400)(3500) = 1400000 characters
Thus, 1400000 bytes for ASCII, and 2800000 bytes for Unicode.

3. What values have binary representations in which only one of the bits is 1? List the binary representations for the smallest six values with this property.
I answered:
Possible binary representations: 0001, 0010, 0100, 1000, 10000, 100000
Therefore 1, 2, 4, 8, 16, and 32.

Question 2 part 2 is not quite right. A Unicode character is not always necessarily 16 bits. UTF-8 for instance, holds ascii 0-127 in a byte and anything else in as many bytes as it takes to resolve the glyph. The byte to character count is encoding dependant.

16 bits would cover a Windows implementation perhaps, with UTF-16 but other encodings will vary.

Unicode has three different encodings - UTF-8 which uses 8 bits and can represent all of ASCII plus 128 extended symbols, UTF-16 which is the basic encoding - it can represent basically everything, and UTF-32 (IIRC) which is not used.