have you tried removing $ sign?
in some languages it just gives the value of it
like
i = (current value)
so its not able to compare
i think
Computer Science Canada unix code |
| Author: | Fonzie [ Fri Nov 16, 2007 5:29 pm ] |
| Post subject: | unix code |
I wasn't sure where to put this so I hope it's in the right place. I'm using a scripting language for the first time and I'm using the bash shell. I'm trying to get a loop to run until a datafile given in the command line has been read through. Here's my code: for ((i=1; i<$#+1; i++)) do while read line do echo $line done < $i done So what I (incorrectly) think this program should do is output every line from every datafile. However the line "done < $i" seems to have a problem. How do I easily address a variable command line argument? |
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| Author: | HeavenAgain [ Fri Nov 16, 2007 7:37 pm ] |
| Post subject: | RE:unix code |
have you tried removing $ sign? in some languages it just gives the value of it like i = (current value) so its not able to compare i think |
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| Author: | OneOffDriveByPoster [ Fri Nov 16, 2007 9:21 pm ] | ||
| Post subject: | Re: unix code | ||
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