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if func = "+" and func2 = "+" and amount = 3 then |
This is the line thats giving you the error. I havn't poured through your code (becuase its long, and I just woke up), but I would assume that func2 is the one that hasn't been declared. You can test this by using a "put func2" just above that line. There are several ways you can fix this.
#1) Reorganize your code into two separate, major if statements. The first one should contain what happens if there were 2 "amount"s, and the second should contain what happens if there were 3.
#2) C has a handy feature where it ignores everything else if the first statement doesn't work, and all the other things are "ands". I'm pretty sure Turing does this as well (I havn't extensively tested this, but eh), so if you just reorganize the if statement, a la
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if amount = 3 and func = "+" and func2 = "+" then |
the compiler will hit the amount = 3 and realise "hey, this isn't true, and theres only ands in this statement. Whats the point in continuing checking here? I'll save the user some run-time and skip the rest of this statement.
Now, a bit more pressing concern of mine is, your program constantly talks about functions, but it doesn't have any. This would make your program quite a bit easier to manage, as you wouldn't have that huge drawn out if-clause. In fact, with clever function management, you could whittle it down quite a bit. Your program also doesn't do order of operations.
An example of what i'm talking about is:
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function mathOp (num1:int,op1:char,num2:int) : int if op1 = "+" then result num1 + num2 end if %you can do the same with the other operations. %if theres an error, then... result num1 end mathOp put mathOp(1,"+",3) %Now, in order to output the answer of three things, you just do: put mathOp(mathOp(1,"+","5),"-",4)%assuming you add the - part into the function. |
Because of the result num1 line, you could just initialize the 'func2' value to something like " " and then allways use the second calling of mathOp that I gave you, and it will only return if func2 is recieved by the user!
Also, what is this:
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if amount = 3 and func2 = "+" then put "Enter 1 number to be calculated: " get num (1) put "Enter another: " get num (2) put "Enter one more: " get num (3) elsif amount = 3 and func2 = "-" then put "Enter 1 number to be calculated: " get num (1) put "Enter another: " get num (2) put "Enter one more: " get num (3) elsif amount = 3 and func2 = "/" then put "Enter 1 number to be calculated: " get num (1) put "Enter another: " get num (2) put "Enter one more: " get num (3) elsif amount = 3 and func2 = "x" then put "Enter 1 number to be calculated:" get num (1) put "Enter another: " get num (2) put "Enter one more: " get num (3) end if |
All of those do the exact same thing, so why do you need an if statement around em?
Anyways, good luck
