Computer Science Canada :: View topic - is c++'s != the same in java?

import java.util.*;
import java.io.*;
public class NumberGuess3
{
public static void main(String[] args)
{
int answer;
String guess = "";
String playAgain = "";
boolean tryAgain = true;
int count = 1;
BufferedReader input = new BufferedReader(new InputStreamReader(System.in));
Random rand = new Random();
answer = rand.nextInt(99) + 1;
System.out.println("Guess the number between 1-100.");
System.out.println("The number is " + answer);
while (tryAgain == true)
{
   try
{
    guess = input.readLine();
}
catch (Exception e)
{
}
if (Integer.parseInt(guess) == answer)
   {
    if (count <= 3)
    System.out.println("Wow, you must be psychic!");
if (count > 3 && count <= 6)
      System.out.println("Not bad, better luck next time!");
    if (count > 6 && count <= 10)
          System.out.println("You need practice!");
if (count > 10)
    System.out.println("Were you even looking at the keyboard?");

    System.out.println("Enter \"yes\" if you want to play again");
    try
    {
          playAgain = input.readLine();
    }
    catch (Exception e)
    {
          System.out.println("input error");
    }

    if (playAgain != "yes")
    tryAgain = false;

    count = 1;
   }
else
    System.out.println("Guess again noob.");
    count += 1;
}

}
}

Author:	Andy [ Wed Mar 01, 2006 8:35 pm ]
Post subject:
in c++ != and == will return u 0 or 1, in java, true != 1 and false != 0

Author:	Justin_ [ Wed Mar 01, 2006 9:32 pm ]
Post subject:
I'm begining to suspect that the readLine() method does something funky. observe: playAgain = input.readLine(); while (playAgain == "yes") { execute this } okay, so if i type in "yes" without quotes, it should do the while loop right?

Author:	Andy [ Wed Mar 01, 2006 9:54 pm ]
Post subject:
two suggestions, check if the string you're comparing with "yes" is indeed just "yes" and no endline character, output the length of the string, and check each character. Also, make sure you're using Java 1.50 if you're going to do that, if not you'll have to use string.equals

Author:	wtd [ Wed Mar 01, 2006 10:17 pm ]
Post subject:
I've given you the answer. If you wish to strip off any extra spaces (newline or otherwise), use the trim method.

Author:	Justin_ [ Wed Mar 01, 2006 10:39 pm ]
Post subject:
I output the length of the word yes and it returns 3. Also I read that the readLine() method does not include the terminating characters or anything like that when writing to a string variable. wtd, if you've given the answer then I don't understand it. A trim method will not help in this situation considering the string is just "yes" so there has to be something else wrong with my program. Whoever can tell me what earns a cookie

Author:	wtd [ Wed Mar 01, 2006 11:25 pm ]
Post subject:
Strings are objects in Java. There's your answer.

Author:	Justin_ [ Wed Mar 01, 2006 11:32 pm ]
Post subject:
oh indeed, thanks so much. When you say equals method I tried the statement with one equal sign lol. But now I understand, thanks.

Author:	[Gandalf] [ Thu Mar 02, 2006 11:28 pm ]
Post subject:
Justin_ wrote: hi Eh? Would I be correct in the assumption that someone has commandeered your account?