filled? like completely?
at atomic number 121 you're going to have 5g1.. so in no naturally occuring (or syntetic for that matter) element.
Though if you excite an atom enough, you could potentially displace an electron into a g orbital.
Bonus points -- at what (hypothetic) atomic number will the h orbital have an electron?
Vince Calder wrote:
The orbitals of an atom are determined by the "principle" quantum number
"N" where (N=1,2,3,4,... ), and then the angular momentum quantum number "L"
where (L= 0, 1, 2,..., (N - 1) ) that is L has values of zero up to N-1 but
no higher. For historical reasons, the L = 0, 1, 2, 3, ... were assigned the
letters: s, p, d, f,... respectively. So if an element existed that had an
atomic number high enough that is N = 5, then it could have values of L =
0,1,2,3,4 -- that is
(s,p,d,f,g,...). For all practical purposes no elements need orbitals with
L>3 or
"f" orbitals. That is not true however of atoms in excited electronic states
where electrons may occupy these higher orbitals, but the analysis and
assignment of the spectra of such atoms is rather complicated.