Quote:
Well if it's still false that means it's wrong and thereforethis whole thread is pointless, as it's nothing but a constant rambling of how you all think you know math
Ravage dude if it pisses you off that much why do you reply? The point is not to prove that 2=1 is false cuz any idiot (such as yourself) can prove that. The point is to prove the initial equation, seemingly flawless, is wrong.
1. a = b
2. a squared = ab
3. a squared - b squared = ab-b squared
4. (a+b)(a-b) = b(a-b)
5. a+b = b
6. b+b = b
7. 2b = b
8. 2 = 1
The problem is step 4. Since a=b then a-b=0. Hence step 4 cannot take place as a divide by 0 is undefined. Why undefined? Well say 1/0 = x. Then 0*x=1. No real number makes the equation 0*x=1 work so that's why it's undefined.
I know this is an old thread... but then why'd you read it?[/quote]