how to add a counter and a add 7 for this problem?

[batman12]

hey,
i'm back. hi i am back. hi i just created this solution but i don't know how to add a counter to count how manny numbers are divisible and how to add the nummber seven and do the same thing as 3 in the same problem?thanks. any help is aprreciated.thanks

code:

for count :1..1000      if   (count mod 3=0 ) then %i need to put number 7 here so it can do the same thing as three     put " The number " ,  count ,  " is divisible by three "     end if     end for put "There are 333 numbers divisible by three from 1 to 100."  %i need help putting a counting that counts this for me without me counting it. thnaks.

[chrispminis]

Well, to do it by 7's you could use remainders, although theres probably a better way. Then just add new variable and add to it when you find a number divisible by 7.

code:

if count rem 7 = 0 then put " The number is currently divisible by seven" countSevens := countSevens + 1 % You can also use countSevens += 1 end if

hope that helps

[Tony]

you could have incremental for loops

code:

for i: 1 .. 100 by 7     ... end for

I think that's the syntax

[Geminias]

Quote:

for count : 1..1000
if (count mod 3 = 0 ) then %i need to put number 7 here so it can do the same thing as three
put " The number " , count , " is divisible by three "
else if (count mod 7 = 0) then
put " The number ", count, " is divisible by seven."
end if

end for
put "There are 333 numbers divisible by three from 1 to 100." %i need help putting a counting that counts this for me without me counting it.

if this is what you are talking about.. then this is how you do it lol. unless you have to check that they are either divisible by seven or three then you can just add "and" between the comparision statements.