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Paul

Thu Apr 01, 2004 6:04 pm


Need help with 2D array problem

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Im suppose to make a program like the carnival ones, where you toss 10 coins onto a mat, the mat is numbered, so you get the same amount of points of the sum of the squares that the coins landed on, I can't seem to get the scoring right, I went to sleep at 3 am today lol, anyone help me find the problem? if you want to see how the squares are originally numbered more clearly, just look at the text file. Also if anyone has any suggestions as to how to make the check easier (other than restructuring my extra if statements), please post. oh yea X means the coin landed there once, Y means the coin landed there twice.


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Delos

Thu Apr 01, 2004 7:18 pm



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Here's a way easier sol'n to it...

Have 2 2-dim arrays.  One of them handles the scores...so, you'd put the text file stuff into that one.

The second one handles the scoring.  You do the tossing of coins into that one.

Then, you do something like this:
- check coinArray (using a, b)
- if an X is found, then score := 1 * numArray (a, b)
- else if a Y is found, then score := 2 * numArray (a, b)
- display score.

Methinks your problem was that your checking was too lengthy and inefficient, thus you may have missed a couple of boxes.

Using 2 arrays means you can increase/decrease the size of the boards and still get everything you need!


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Paul

Thu Apr 01, 2004 7:24 pm



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omg thank you thank you thank you, that was the most obvious way of checking it, yet I hadn't thought about it! damn some kind of brain block, but then Im so spaced out, its like Im typing and I dunno I was typing...


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Paul

Thu Apr 01, 2004 7:45 pm



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Ok I just figured it out, there was nothing wrong with my previous really tedious checking code I just figured it out... thanx for helping me reduce 50 lines to 6 lines though, thanx alot. But it all came down to the right checking but wrong display,
this code

 for a : 1 .. 6
        for b : 1 .. 6
            if b = 1 then
                x := 195
            end if
            Font.Draw (board (a, b), x, y, font, black)
            x += 67
        end for
        y -= 66
    end for

goes after

 if board (px, py) = "X" then
        board (px, py) := "Y"
    end if
    if board (px, py) not= "X" and board (px, py) not= "Y" then
        board (px, py) := "X"
    end if

this code, b4 that, they were switched, so the last X wouldn't get drawn, and I would think I got the freaking scoring wrong. God damn it I wish there was a way to stop making these damned stupid tiny mistakes that are so freaking time consuming.


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Delos

Thu Apr 01, 2004 8:51 pm



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Oh, but there is!

It's called "not staying up until 3 am unless you're not going anywhere the next day (well, that day by then)"

 :wink: