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Panphobia

Wed Apr 17, 2013 11:51 pm


Throwing exception in Java

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The traditional way I would throw an exception in a method/function I would just put throws @@@@@@@@Exception, but I recently found out while coding a BFS for a sliding puzzle game that you can throw an illegal exception just by putting 0/0 here is an example [code]return (three.indexOf(car) != -1) ? 3 : two.indexOf(car) != -1 ? 2 : 0 / 0;[/code]now I just wanted to ask why does that throw an illegal argument exception, and nowhere on the internet could I find an answer for that. If anyone knows could you clear that up? Thanks!


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Tony

Thu Apr 18, 2013 12:16 am


RE:Throwing exception in Java

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stacktrace please.