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unoho

Tue Oct 05, 2010 7:45 pm


array inside a function

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hey guys, im having problem in the following code

[code]
int function(int array[], int n){
    int b[n];

}
[/code]

everytime i try that, the IDE gives me an error sometime about c89 ISO etc. etc. anyone knows what that means? but when i change that n to some number, it works fine. any ideas/comments is much appreciated.


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TheGuardian001

Tue Oct 05, 2010 8:05 pm


Re: array inside a function

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What IDE/Compiler are you using?
I have no problems with similar code using gcc.

Oh, and what specific error is it giving you? C89 is a rule set (and a fairly old one at that,) not an error.


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unoho

Tue Oct 05, 2010 8:59 pm


Re: array inside a function

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it says 
- ISO C89 forbids variable-size array 'a' "
- ISO C89 forbids mixed declarations and code
- unsuccessful build

i tried it on Quicny 2005 and DevC++ and both r same.

so from what i can understand, u can't put a variable as an array size?

EDIT: OMG this is soo stupid, it works fine when i try to do it in command prompt using gcc 3.4.5 but it wont work with the IDEs


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TheGuardian001

Tue Oct 05, 2010 9:18 pm


Re: array inside a function

-----------------------------------

From what I understand,  it depends on what version of the C standard your compiler uses.

C89 doesn't allow it, C90 doesn't allow it, however C99 does. Since your compiler uses C89, you won't be able to do this without switching/updating your compiler.

Edit: If your IDE uses GCC (MinGW on windows,) you can force it to use C99 by adding the -std=c99 (case sensitive, c99 not C99,) so long as your version of it supports the c99 standard.


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unoho

Tue Oct 05, 2010 9:56 pm


RE:array inside a function

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thank you soo much. by default, the IDE had the C99 option unchecked for c programs. but ya..had to spent 4 hours trying to fix this problem :S
but at least i know how to use command promt to get to running gcc:D:D


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coolgod

Sat Oct 09, 2010 12:22 am


Re: array inside a function

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how is the compiler suppose to allocate memory for the program if it doesn't know how much space it need?
this isn't a dynamic array.....


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TheGuardian001

Sat Oct 09, 2010 12:42 am


Re: array inside a function

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how is the compiler suppose to allocate memory for the program if it doesn't know how much space it need?
this isn't a dynamic array.....
This isn't an attempt to make a dynamic array. The purpose of this is to create an array of size x (useful in a function, if it needs a temporary array of size that will be determined when the function is called.) So long as x has a value when the array is created, the compiler knows exactly how much space to allocate (x*sizeof(type).)
IE:
[code]
int x = 4;
int y[x]; //same as int y[4];
[/code]
x resolves to 4, thus this array has 4 elements, and always will.
This is not a problem for most modern compilers. Any compiler that conforms to the C99 specifications (however not one that conforms to C89/ANSI C) can do this.


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DtY

Sat Oct 09, 2010 3:08 pm


Re: array inside a function

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how is the compiler suppose to allocate memory for the program if it doesn't know how much space it need?
this isn't a dynamic array.....Which is why there was a problem. Nondymanic arrays with a size computed at runtime wasn't a standard feature of C until C99 (and many people still think it's nonstandard).


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ncvitak

Sun Jun 09, 2013 6:16 pm


Re: array inside a function

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In C to use an array as a function parameter you must pass it as a pointer.
Example:
#include 

int a


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Nathan4102

Sun Jun 09, 2013 6:25 pm


RE:array inside a function

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Please don't gravedig old posts. This thread has been dead for almost 3 years now.


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ncvitak

Sun Jun 09, 2013 6:27 pm


RE:array inside a function

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Maybe he still wants help :)


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Raknarg

Sun Jun 09, 2013 6:43 pm


RE:array inside a function

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Necroposting is ok as long as the poster has some new content, I believe. Posts such as "wow thats cool" or "thanks" are frowned upon