----------------------------------- Thuged_Out_G Sun Dec 14, 2003 3:28 am ASCII to binary ----------------------------------- how do you figure out the binary value of an ASCII char/word? i want to make a program to do this, but i cant do that until i know how to convert ASCII to binary ----------------------------------- Tony Sun Dec 14, 2003 3:49 am ----------------------------------- well you get the ASCII value using ord() put ord("a") then use intstr() fucntion to convert it to binary :lol: put intstr(ord("a"),0,2) ----------------------------------- Thuged_Out_G Sun Dec 14, 2003 3:51 am ----------------------------------- put intstr(ord("a"),0,2) what does the ,0,2) mean? [/code] ----------------------------------- Tony Sun Dec 14, 2003 4:06 am ----------------------------------- 0 is the length out returning value... works the same as :# after a string, so 0 will not affect the output in any way. 2 is the base to which the number is converted to. 8 will make output a hex. ----------------------------------- Dan Tue Dec 16, 2003 12:37 pm ----------------------------------- yes tony come to dark side with me, use the intstr :twisted: just to let you know that if that is for school your teacher may not like intstr it kind of takes the calangen out of making a to any bases convertor :twisted: ----------------------------------- Thuged_Out_G Tue Dec 16, 2003 4:03 pm ----------------------------------- no its not for school, i was just interested in how it was done after i downloaded tony's one in VB, i think it was tony who did it ----------------------------------- santabruzer Tue Dec 16, 2003 5:02 pm ----------------------------------- so that's the simple of converting to binary... . :oops: .. i was using the div 2 and rem 2 dealy.. the same way as by hand.. now it's so simple.. ----------------------------------- PaddyLong Tue Dec 16, 2003 5:35 pm ----------------------------------- hex is base 16 .... base 8 is octal ----------------------------------- Tony Tue Dec 16, 2003 6:11 pm ----------------------------------- for my VB one, you basically grab the ord() value of the letter and turn that number into binary. start from 2^8 and move down. If the number is larger then or equals to 2^counter then bit is 1, subtract value from number, else bit is 0. And so on until 2^0. ----------------------------------- Andy Tue Dec 16, 2003 8:01 pm ----------------------------------- why use rem when u can use div? ----------------------------------- PaddyLong Tue Dec 16, 2003 8:42 pm ----------------------------------- you use the remainder because any number divided by 2 will give a remainder of 0 or 1 ... so to convert from base 10 (decimal) to base 2 (binary) you just keep dividing by two and keeping track of the remainder... ex.. 25 / 2 = 12 R 1 12 / 2 = 6 R 0 6 / 2 = 3 R 0 3 / 2 = 1 R 1 1 / 2 = 0 R 1 then you read from the bottom up and record the remainders... so 25 base 10 = 11001 base 2 another way is to use the greatest power of 2 that's less than the number... 25-16 = 9 9 - 8 = 1 1 - 1 = 0 so this means you have the 1, 8 and 16 bits set... 11001 ----------------------------------- Andy Tue Dec 16, 2003 8:44 pm ----------------------------------- i meant to say mod