
-----------------------------------
octopi
Sun Dec 07, 2003 10:13 pm

f(x) == f(10x)
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100 bits for someone who solves the following problem:

Find a function f(x), where f(x) is equal to f(10x) for all values of x, 
The varible x must be used in the function.

example of how not to do it:
f(x) = 4
f(x) can't be 4 (because, the result would be 4 for all values of x), and x is not used in the function.

f(x) = 4+x-x
NO, because when simplified you get 4, cheap bastards.


Good luck.

Any cheapory in your anwsers will result in me not giving you bits...aka stupid anwser thats not right. but I didn't cover above in my examples of how not to do it.
(like,   f(x)= 0x, or f(x)= x^0)

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Mazer
Mon Dec 08, 2003 9:16 am

Re: f(x) == f(10x)
-----------------------------------
f(x)= 0x

crap!!! now i have to come up with something else! :evil:

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McKenzie
Mon Dec 08, 2003 10:05 am


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int f(int x)
{
     while(x % 10 == 0)
          x = x / 10;
     return x;
}


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Tony
Mon Dec 08, 2003 10:13 am


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:lol:

wait :? Is the question about a math function or a programming function :think:

btw, McKenzie - since when do you have those billion bits?
and for that matter... where did half of my bits go? :think:

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McKenzie
Mon Dec 08, 2003 10:36 am


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I think it is supposed to be a math question. I thought a compsci answer was better :wink:  bits...what bits?

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Tony
Mon Dec 08, 2003 10:41 am


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bits...what bits?

:think: umm... can Andy create bits now that he's a mod :think:

*Tony takes out his sniper rifle and goes to investigate* :snipe:

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Blade
Mon Dec 08, 2003 1:20 pm


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wow, how quickly topics get changed around from the initial equation..

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Andy
Mon Dec 08, 2003 7:29 pm


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f(x)=[1/x]

take off the top bar of the square bracket. that is actually a mathematical operator, it means the largest integer smaller than the number contained.... heh that works... but only for integral values of x

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AsianSensation
Mon Dec 08, 2003 7:33 pm


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actually that one works for every single number except for 1 itself.

[1/1] = 1, [1/10] = 0

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Andy
Mon Dec 08, 2003 7:40 pm


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dope!

fine [1/x+1]

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AsianSensation
Mon Dec 08, 2003 7:42 pm


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nope, still another fault.

[1/(-10 + 1)] = -1, [1/(-1 + 1)] = undefined

still not every single number.

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Andy
Mon Dec 08, 2003 8:48 pm


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okok i think i actually got it...
f(x)=[(x-(|x|/x))/x]

how about that?

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Mazer
Mon Dec 08, 2003 9:07 pm


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hey dodge, besides the fact that f(x) != f(10x) with your function, what is f(0)?

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Andy
Mon Dec 08, 2003 9:20 pm


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yes it does equal... sub in any value... and undefined=undefined rite?

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Mazer
Mon Dec 08, 2003 9:41 pm


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uh... as we all know, i really suck at math, so feel free to point out my stupidity if i do something that seems incredibly n00bishly stupid.

f(x)=

f(5) = (5 - (|5|/5))/5
      =  (5 - 1) / 5
      = 4/5
      = 0.8

right?

f(50) = (50 - (|50|/50))/50
        = (50 - 1)/50
        = 49/50
        = 0.98

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Andy
Mon Dec 08, 2003 10:30 pm


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f(x)=

it was from my previous quote... the [] withought the top bar of the bracket was intended

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rizzix
Mon Dec 08, 2003 11:14 pm


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allright i give up.. whats the answer?

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bugzpodder
Mon Dec 08, 2003 11:18 pm


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f(x)=|x|/x  with f(0) arbitrary
or you can obviously define your own functions
for example we can make an arbitrary function in the interval [a,10a] where f(a)=f(2a) and then we are define f for all reals by a translation + horizontal stretch by a factor of 10^n

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bugzpodder
Mon Dec 08, 2003 11:24 pm


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and since the original question did not specifically state the domain of x, we could let x simply be positive integers and one could use the number theoritical function to obtain
f(x)=phi(10x)/x, where phi is defined as Euler's Totient Function
http://mathworld.wolfram.com/TotientFunction.html

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PaddyLong
Tue Dec 09, 2003 12:08 am


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yes it does equal... sub in any value... and undefined=undefined rite?

... well, isn't that kind of like saying the root of -5 is the same as the root of -1 ? ....

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Andy
Tue Dec 09, 2003 11:53 am


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noooo... sqrt(-5)=sqrt(5)i
             sqrt(-3)=sqrt(3)i

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PaddyLong
Tue Dec 09, 2003 11:59 am


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yes, I know... but roots of negative numbers are undefined in the real number system...

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Andy
Tue Dec 09, 2003 12:48 pm


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when i said undefined i meant undefined... in all number systems

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PaddyLong
Tue Dec 09, 2003 4:11 pm


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kk  8)

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bugzpodder
Thu Dec 11, 2003 10:01 am


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so where are my bits? ;)
