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NEOS

Sun Dec 07, 2008 5:48 pm


Pseudocode problem

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This is my code and I just need to know if that's how I make it ask for the password 5 times, using the for loop.

% Write a pseudocode for a program that checks to see if a password is valid.
% The criteria for the password are listed below. The user must enter in the
% password and a message must be given if the password is valid or invalid.
% If it is invalid the program must allow the user to enter in a new one;
% and again, up to 5 times.

/*
 Variables password : String
 For i : 1..5
 Get password

 Function Capletter (Cap:Int)
 Check the ASCII Code Of password(1),password(2),password(3),password(4),password(5),password(6),password(7),password(8),password(9),password(10),password(11),password(12)
 If The ASCII Of each Letter Equals Between 65 And 90 Then
 Display Password is Valid Message
 Else
 Display Password is Invalid Message
 The Result is If The password has at least one ASCII code
 End Capletter

 Function Oneletter (Lett:Int)
 If the ASCII code For password (1) Equals Between 65 And 90, 97 And 122 Then
 Display Password is Valid Message
 Else
 Display Password is Invalid Message
 The Result is If The password has at least one ASCII code
 End Oneletter

 Function Onepun (pun:Int)
 If the ASCII code For password (1) Equals Between 33, 63, 46 Then
 Display Password is Valid Message
 Else
 Display Password is Invalid Message
 The Result is If The password has at least one ASCII code
 End Onepun

 Function Onenum (num:Int)
 If the ASCII code For password (1) Equals Between 48 And 57 Then
 Display Password is Valid Message
 Else
 Display Password is Invalid Message
 The Result is If The password has at least one ASCII code
 End Onenum

 If the Password Does not Have a Puncuation mark, One letter, one Number, a Capital letter, At Least 6 charecters And A max of 12 letters then
 Display Password is Invalid Message
 elsif Password Does Have a Puncuation mark, One letter, one Number, a Capital letter, At Least 6 charecters And A max of 12 letters then
 Display Password Is Valid Message
 end if
 
 End for
/*


That's my code and I just need to know if that's how I make it ask for the password 5 times, using the for loop.


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syntax_error

Sun Dec 07, 2008 7:23 pm


RE:Pseudocode problem

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var count.


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Insectoid

Sun Dec 07, 2008 7:23 pm


RE:Pseudocode problem

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You don't need to check the ascii values, you can do 
if pass[1] > A and pass[1]= 'A'

is the same as

ord(pass[1]) >= ord('A')


Though ultimately you are still checking if a character is in a certain numeric range, even if you don't explicitly specify the conversion.


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Insectoid

Sun Dec 07, 2008 9:20 pm


RE:Pseudocode problem

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Yeah, it does the same thing. It just reads better and requires less typing.


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DanielG

Sun Dec 07, 2008 9:49 pm


RE:Pseudocode problem

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Turing basically does the ascii conversion for you when comparing them.


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andrew.

Mon Dec 08, 2008 4:25 pm


RE:Pseudocode problem

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It would be something like this:

Constant:
password - The real password (string)

Variables:
passattempt - The password the user enters (string)
counter - A counter to check how many times you entered in a password (integer)

Main loop:
Clear screen
Print "Enter the password"
Get passattempt
Check if passattempt equals the password
If it does, then exit the loop
If it doesn't then add one to counter and say how may login attempts you used (counter out of 5)
Check if counter equals 5
If it does, then quit (not exit, terminate the program)

After the loop:
Whatever you want