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Flikerator

Tue Jun 13, 2006 5:37 pm


Math - Sequences/Series

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Im doing a math assignment right now, and the question is this;

If t[n] = ((t[n-1])**2) + 4n-1 and t[1]=1, find terms t[2] through t[5].
Where the values in [] are subscripts.

So if im doing t[2];

t[2] = ((t[2-1])**2) +4(2)-1
      = ((t[1])**2) + 7

Would this be 8? Because t[1] = 1?

In which case, this would be recrusive, which I can do. I just need to know if its right so I don't mess everything up ><

Edit: Also, wouldn't the "**2" always result in 1??


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Cervantes

Tue Jun 13, 2006 6:08 pm



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Standard notation for subscripts would look like "t_n" where n is a subscript for t.

That's right. t_2 would be 7.

No, squaring t_n-1 does not always result in 1. What if n = 3? Then n-1 = 2. t_2 is not 1, it's 7. So 7 ** 2 is 49, not 1.


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Mazer

Tue Jun 13, 2006 6:09 pm



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Looks ok to me. Except for the **2 always giving one. When you're trying to find t[3], you'll be subbing in t[2], so it'd be 8**2 that time.


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Flikerator

Tue Jun 13, 2006 6:34 pm



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Where {S} = Sigma Notation (ie upper case greek letter Sigma);

EDIT: t
 n
{s}i**3 =[ (n(n+1))**2 ] / 4